README
Solving Codeforces problem
I. Welcome for you with Conditions : https://codeforces.com/group/MWSDmqGsZm/contest/219158/problem/I
#include <stdio.h>
int main()
{
int a, b;
scanf("%d %d", &a, &b);
if (a >= b)
{
printf("Yes");
}
else
{
printf("No");
}
return 0;
}
J. Multiples : https://codeforces.com/group/MWSDmqGsZm/contest/219158/problem/J
#include <stdio.h>
int main()
{
int a, b;
scanf("%d %d", &a, &b);
if (a%b == 0 || b%a == 0)
{
printf("Multiples");
}
else
{
printf("No Multiples");
}
return 0;
}
P. First digit ! https://codeforces.com/group/MWSDmqGsZm/contest/219158/problem/P
#include <stdio.h>
int main()
{
int x;
scanf("%d", &x);
// find the first digit as dividing int with int will be become int number even if it come fractional like 365/10 = 36.5 it will be 36
// for finding first digit 4569/1000 = 4
int firstDigit = x / 1000;
if (firstDigit % 2 == 0)
{
printf("EVEN");
}
else
{
printf("ODD");
}
return 0;
}
- eliminating last digit
#include <stdio.h>
int main()
{
int x;
scanf("%d", &x);
int last_digit = x % 10;
printf("%d \n", last_digit);
if (last_digit % 2 == 0)
{
printf("EVEN");
}
else
{
printf("ODD");
}
return 0;
}
Understanding character

#include <stdio.h>
int main()
{
char c = 'B';
printf("%c", c);
printf("%d", c); // as memory stores asci value of the char it will show result as well asci value of b is 66
// char keep 1 byte = 8 bit means 2 ^ 8 = 256 char we can store
return 0;
}
- value to char and char to value conversion can be done
N. Char : https://codeforces.com/group/MWSDmqGsZm/contest/219158/problem/N
#include <stdio.h>
int main()
{
char x;
scanf("%c", &x);
if (x >= 'a' && x <= 'z')
{
x = x - 32;
printf("%c", x);
}
else
{
x = x + 32;
printf("%c", x);
}
return 0;
}
M. Capital or Small or Digit : https://codeforces.com/group/MWSDmqGsZm/contest/219158/problem/M
#include <stdio.h>
int main()
{
char ch;
scanf("%c", &ch);
if (ch >= '0' && ch <= '9')
{
printf("IS DIGIT");
}
else
{
printf("ALPHA \n");
if (ch >= 'a' && ch <= 'z')
{
printf("IS SMALL");
}
else
{
printf("IS CAPITAL");
}
}
return 0;
}
K. Max and Min : https://codeforces.com/group/MWSDmqGsZm/contest/219158/problem/K
#include <stdio.h>
int main()
{
int a, b, c;
scanf("%d %d %d", &a, &b, &c);
// min among them
if (a <= b && a <= c)
{
printf("%d ", a);
}
else if (b <= a && b <= c)
{
printf("%d ", b);
}
else if (c <= a && c <= b)
{
printf("%d ", c);
}
// max among them
if (a >= b && a >= c)
{
printf("%d", a);
}
else if (b >= a && b >= c)
{
printf("%d", b);
}
else if (c >= a && c >= b)
{
printf("%d", c);
}
return 0;
}
- more
#include <stdio.h>
int main()
{
long long A, B, C, D;
scanf("%lld %lld %lld %lld", &A, &B, &C, &D);
long long result = A * B - C * D;
printf("Difference = %lld", result);
return 0;
}
#include <stdio.h>
int main()
{
int x, y;
scanf("%d %d", &x, &y);
int sum = x + y;
long long int mult = x * y;
int sub = x - y;
printf("%d + %d = %d\n", x, y, sum);
printf("%d * %d = %lld\n", x, y, mult);
printf("%d - %d = %d", x, y, sub);
return 0;
}